- 3( 14 - 6/3 y) - 2 ( y - 1/4 ) =

4y + -83/2

Step-by-step explanation:

−3 (14− 6 /3 y) −2 (y− 1 4 )

=(−3) (14) + (−3) (−2y) + (−2) (y) +(−2) ( −1 /4 )

= −42 + 6y + −2y +  1 /2

= −42 + 6y + −2y + 1/2

= (6y + −2y) + (−42 + 1/2)

=4y + -83/2

3 is greater then both of those numbers

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value