Arocket is launched from atop a 105-foot cliff with an initial velocity of 156 ft/s. the height of the rocket above the ground at time t is given by h = –16t2 + 156t + 105. when will the rocket hit the ground after it is launched? round to the nearest tenth of a second.

4.9 s
9.8 s
0.6 s
10.4 s

The correct option is 4. The rocket will hit the ground after 10.4 s.

Step-by-step explanation:

The given function is

Where, h is height of the rocket above the ground at time t.

The rocket will hit the ground, when h=0.

Using quadratic formula

The time can  not negative, therefore after 10.382 second the rocket will hit the ground.

Therefore the correct option is 4. The rocket will hit the ground after 10.4 s.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

agree

step-by-step explanation: