he National Center for Health Statistics interviewed 5409 adult smokers in 2015, and 2666 of them said they had tried to quit smoking during the past year. Consider this to be a random sample. Find a 95% confidence interval for the proportion of smokers who have tried to quit within the past year. (Round the final answers to three decimal places.) The 95% confidence interval is ( , ).

95% confidence interval for the proportion of smokers who have tried to quit within the past year

(0.47956 ,0.50620)

Step-by-step explanation:

Step(i):-

Given that  National Center for Health Statistics interviewed 5409 adult smokers in 2015

Sample size 'n' = 5409

Given that 2666 of them said they had tried to quit smoking during the past year.

proportion

             Q = 1 - P = 1 - 0.49288 = 0.50712

Step(ii):-

95% confidence interval for the proportion of smokers who have tried to quit within the past year

(0.49288 - 0.01332 , 0.49288+0.01332)

(0.47956 , 0.50620 )

Final -

95% confidence interval for the proportion of smokers who have tried to quit within the past year

(0.47956 ,0.50620)

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step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.