Find the probability. an irs auditor randomly selects 3 tax returns (without replacement) from 47 returns of which 5 contain errors. what is the probability that she selects none of those containing errors?

a. 0.0012

b. 0.0006

c. 0.708

d. 0.7136

Number of returns = 47
Number of returns that contain errors = 5
Number of returns that does not contain error = 47 - 5 = 42

P(selecting none that contains error in the unreplaced selection) = 42/47 x 41/46 x 40/45 = 68880 / 97290 = 0.708

option C is the correct answer.

Here are the answers to the ones that i could see.