= O LINEAR The length of a rectangle is 6 cm longer than its width.
If the perimeter of the rectangle is 56 cm, find its length and width.
cm
Х
length: 0
width: Ich
?
cm

I. L = 17 cm.

II. W = 11 cm.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangle = 56cm

Translating the word problem into an algebraic expression, we have;

L = W + 6 equation 1

The perimeter of a rectangle is given by the formula;

P = 2(L + W)

56 = 2(L + W) equation 2

Substituting eqn 1 into eqn 2, we have;

56 = 2(W + 6 + W)

56 = 2(6 + 2W)

Opening the bracket, we have;

56 = 12 + 4W

4W = 56 - 12

4W = 44

W = 44/4

W = 11 cm

Next, we would find the length of the rectangle;

From eqn 1;

L = W + 6

L = 11 + 6

L = 17 cm

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead