A golfer hits a ball that follows the path of g(x) = -16x^2 + 78x + 10 . The golfer is teeing off from an elevated position where g(x) represents the height of the ball as x represents time in seconds 1. what is the initial height of the ball ?

2. when is the ball the highest ?

3. how long is the ball in the air ?

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Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )