in triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. Find the perimeter of trapazoid BMNC.

35

since m and n are the midpoints of ab and ac resistively

then ,bc=2mn=16

since m and l are the midpoints of ba and bc respectively

then, ac =2mn =10

then,nc =1/2 × 10 =5

similary, mb=6

then ,perimeter=nc+mb+mn+bc=5+6+8+16=35

36

step-by-step explanation: