The surface area of the square pyramid shown is 84 square inches. What is the value of $x$ ? Square pyramid with base edge of 6 inches, and a slant height labeled x inches, on a triangular face.

4 inches

Step-by-step explanation:

The surface area, A of a right square pyramid is given by :

A = a² + 2as

Where, s = height of each triangular surface = x

a = base edge of pyramid

Substituting values into the equation :

A = 84 in² ; a = 6 in ; Slant height, s = x

84 = 6² + 2(6 * x)

84 = 36 + 2(6x)

84 = 36 + 12x

84 - 36 = 12x

48 = 12x

48/12 = 12x / 12

4 = x

Hence, Slant height, x = 4 inches

4 inches

Step-by-step explanation:

The surface area, A of a right square pyramid is given by :

A = a² + 2as

Where, s = height of each triangular surface = x

a = base edge of pyramid

Substituting values into the equation :

A = 84 in² ; a = 6 in ; Slant height, s = x

84 = 6² + 2(6 * x)

84 = 36 + 2(6x)

84 = 36 + 12x

84 - 36 = 12x

48 = 12x

48/12 = 12x / 12

4 = x

Hence, Slant height, x = 4 inches

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11