A farmer in China discovers a mammal hide that contains 29% of its original
amount of C-14.
N=Noekt
No = inital amount of C-14 (at time
t = 0)
N = amount of C-14 at time t

I'm sorry this isn't the answer, but I just want you to know that you are incredible and that I love you for you

Step-by-step explanation:

Step-by-step explanation:

t = 12040 years

N=NOe^-kt

N = amount of C-14 at time t

NO = initial amount of C-14

k= 0.0001

t = time (unknown)

We know that the amount found is 30% of the original. Therefore we can simply set N to 30 and NO to 100 because 30% of 100 is 30. Really you can give any amount, but setting it at 100 is the easiest, so long as N is 30% of NO.

so if we set the problem up again using all the given values and the new ones we assigned:

N= 30

NO = 100

30=100e^-0.0001(t)

Remember, you are solving for t, so you have to try and manipulate the formula to get t by itself on one side.

We can divide both sides by 100 and you are left with:

.30=e^-0.0001(t)

You can see that you have "e" which means we can use natural log to get rid of e:

e^y = x and ln(x) = y

.30=e^-0.0001(t)

using the natural log,

.30 = x

-0.0001(t) = y

Therefore:

ln (x) = y

ln (.30) = -0.0001(t)

plug in the value ln(.30) into a calculator and you get:

-1.20397 = -0.0001(t)

*NOTE: normally it would not work if you have a negative answer because you cannot have negative years, however, there is a negative on the other side of the equation which will cancel out so it works in this case.

now to solve for t, we simply divide both sides by -0.0001

Therefore

t = 12039.7

But you have to round to the nearest year so

t = 12040

**NOTE: the k value given (which is the rate at which C-14 decays each year) is very small. That means that you will have a large value for time because it takes so long for the C-14 to decay every year.

Hope that helped :)

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

answer: you need the equation in the question so i can answer it

step-by-step explanation: