The locus of points in a plane

We're talking about a set of points already in a plane, so consider the x-y plane, in which the equations y = 5 and y = -3 correspond to vertical lines. All the points equidistant from both lines would fall on the vertical line right in the middle of y = 5 and y = -3, which we can get by taking the average:

(5 + (-3)) / 2 = 2 / 2 = 1

So this locus is the single vertical line y = 1.

y = 1.

Step-by-step explanation:

We're talking about a set of points already in a plane, so consider the x-y plane, in which the equations y = 5 and y = -3 correspond to vertical lines. All the points equidistant from both lines would fall on the vertical line right in the middle of y = 5 and y = -3, which we can get by taking the average:

(5 + (-3)) / 2 = 2 / 2 = 1

So this locus is the single vertical line y = 1.

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

i need a diagram

step-by-step explanation:

no