triangle PQR is similar to triangle XYZ if PQ = n + 2, QR = n - 2 and XY=n^2 - 4, what is the value of YZ, in terms of n?

(n-2)²

Step-by-step explanation:

If triangle PQR is similar to triangle XYZ, then;

PQ/QR =XY/YZ

Given

PQ = n + 2,

QR = n - 2 and

XY=n^2 - 4,

Substitute

n+2/n-2 = n²-4/YZ

n+2/n-2 = (n+2)(n-2)/YZ

1/n-2 = n-2/YZ

Cross multiply

YZ = (n-2)(n-2)

YZ = (n-2)²

Hence the value of YZ in terms of n is (n-2)²

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