Mathematics, 02.09.2019 17:30 Renebebe1

The figure shows the potential energy of a 400g particle as it moves along the x-axis. suppose the particle's mechanical energy is 12 j.
where are the particle's turning points?
what is the particle's speed when it is at x= 2.0m?
what is the particle's maximum speed?
at what position or positions does this occur?

The figure shows the potential energy of a 400g particle as it moves along the x-axis. suppose the p

Answers: 1

Show answers

Answers

Answer from: jordanlopezorosco16

1) The turning points are at x = 1, x = 2, x = 4.

2) At x = 2, P.E = 8 J
So KE = 12 - 8 = 4 J
4 = 1/2 x 0.4 x v²
v = 4.47 m/s

The maximum speed is when K.E = 12 J
12 = 1/2 x 0.4 x v²
v = 7.74 m/s

This occurs at the points where P.E is 0, so at x = 1 and x = 4

Answer from: jonzyjones3114

the particle's turning points : x = 1, x = 2, x = 4.

the particle's speed when it is at x= 2.0 : v = 4,472 m/s

the particle's maximum speed : v = 7,746 m/s, at x=1 and x=4

Further explanation

Energy is the ability to do work

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

$\large{\boxed{\bold{KE=\frac{1}{2}mv^2}}}$

So for two objects that have the same speed, the greater the mass of the object, the greater the kinetic energy

Whereas for a stationary object it has kinetic energy = 0

While the energy produced from its position is called potential energy (PE)

which can be formulated as:

Ep = m. g. h ⇒ gravitational potential energy

The sum of kinetic and potential energy is called mechanical energy

ME = KE + PE turning points

The particle's turning points is the point where the particle changes its direction of motion, because the motion of a particle can be considered as a vector

In the picture, turning points are shown at x = 1, x = 2, x = 4.

the particle's speed when it is at x = 2.0 m :

The potential energy (PE) value in the figure when x = 2 is 8 J

Because it is known that ME = 12 J, particle velocity can be found from the kinetic energy equation

KE = ME - PE

KE = 12 - 8

KE = 4 J

$\rm KE=\frac{1}{2}mv^2\\\\m=400\:g=0.4\:kg\\\\4=\frac{1}{2}0.4.v^2\\\\v=4,472\frac{m}{s}$

the particle's maximum speed

The maximum particle velocity occurs when PE = 0 and KE = ME

The lowest particle velocity occurs when KE = 0 and PE = ME

So :

KE = ME

$\rm KE=1\:J\\\\12=\frac{1}{2}.0.4.v^2\\\\v=7,746\frac{m}{s}$

The position when the particle on the maximum speed (PE = 0) occurs when particles at x = 1 and x = 4

Learn more

The kinetic energy of the vehicle

link

law of motion

link

displacement of A skateboarder

link

Keywords: kinetic energy, speed,particle,turning points, motion, work, potential energy, mechanical energy

Answer from: Quest

Find the perimeter of the figure shown above with a side length 5 units.(each figure is a square).a.10 unitsc.30 unitsb.20 unitsd.40 units select the best answer from the choices providedabcdmark this and return

Answer from: Quest

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

Another question on Mathematics

Mathematics, 21.06.2019 13:00

Which equation requires the division property of equality to be solved?

Answers: 1

Answer

Mathematics, 21.06.2019 16:00

Which term best describes the association between variables a and b? no association a negative linear association a positive linear association a nonlinear association a scatterplot with an x axis labeled, variable a from zero to ten in increments of two and the y axis labeled, variable b from zero to one hundred forty in increments of twenty with fifteen points in a positive trend.

Answers: 3

Answer

Mathematics, 21.06.2019 22:20

Given the following linear function sketch the graph of the function and find the domain and range. ƒ(x) = -5x + 4

Answers: 2

Answer

Mathematics, 22.06.2019 03:20

Each unit cost 14p, how much would 942 units cost?

Answers: 1

Answer

You know the right answer?

The figure shows the potential energy of a 400g particle as it moves along the x-axis. suppose the p...