Find the area of circle x that has a radius XY at coordinates X=(0,2) Y=(3,2). Round to the nearest hundredth place and show your work.​

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the median is   36 orr sum like dat

step-by-step explanation: