In parallelogram defg, dh = x + 3, hf = 3y, gh = 4x – 5, and he = 2y + 3. find the values of x and y.

Here, DH = HF 

x+3 = 3y

x = 3y-3   (I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is      x=3  & y=2

europa2433

europa2433

step-by-step explanation:

6.5

step-by-step explanation:

you said it was in the question

~courtney