1. 4-5c=6+9(8-7c) 2. -4=-9b*2+9b
3. 32c+12=2c+3(4+10c)
4. 70(n+4)-224=7(10n+8)
5. 3(r+10)=7-(3r-23)
6. 6+10r=9(7-4r)

State whether each question has one, infinite, or no solution. If just one solution solve the variable

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

b and c

correct answer is c. just did it

step-by-step explanation: