Acircle its center at the center of a square with 8 inch sides. find the area of the square not covered by the circle. round the answer to the nearest tenth.
a) 57.1 in²
b) 9.1²
c) 2.0²
d) 13.7 in²

To find the area of the square not covered by the circle. We need to find the area of the two shapes and subtract the area of the square with the area of the circle. We calculate as follows:

A(square) = s²
A(square) = (8 in)²
A(square) = 64 in²

A(circle) = πr²
A(circle) = π(8/2)²
A(circle) = 16π in²

A = 64 - 16π = 13.73 in²

Idon’t understand what you’re asking..