If the sum of six consecutive odd integers is 252, what is the smallest of the six integers?

37  smallest number

Step-by-step explanation:

If your integer is x

The next 5 odd integers are:

x+2

x+4

x+6

x+8

x+10

x+x+2+x+4+x+6+x+8+x+10=252

6x+30=252

6x=252-30

6x=222

x=222/6

x=37

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13