A doughnut shop wants to determine if there is a difference in donut sales at different times of the day and for different types of doughnuts. They are open in the morning, afternoon, and night, and offer the following flavors: vanilla, chocolate, red velvet, and marbled. There were a total of 48 sales recorded. The shop conducted a two-way ANOVA test and found an F test statistic for Flavor of 14.87. What would be the numerator degree of freedom for the F test statistic to determine if the factor flavor was significant

Solution :

Let

= number of levels for the factors 'flavors' = 4

      (4 levels vanilla, chocolate, red velvet and marbled)

The degree of freedom for the factor 'flavors' = - 1

                                                                            = 4 - 1

                                                                            = 3

Now defining the F test statistics for testing the significance of the factors, 'flavors' :

F test statics =          ,   Ms = mean square

where F = , error df.

Thus the numerator degrees of the freedom for the F test statistics to determine if the factor flavor was significant is = - 1

                                                                            = 4 - 1

                                                                            = 3                                                                              

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.