3. (5 points) A company wishes to estimate the mean monthly electric bill. If the standard deviation is $400, how large a sample is required to estimate the mean electric bill to within $100

with 98% confidence?

9.304

Step-by-step explanation:

company wishes to estimate the mean monthly electric bill. If the standard

deviation is $400, how large a sample is required to estimate the mean electric bill to within $100

with 98% confidence?

Sample size, n = (Zcritical * σ) ÷ ME

σ = standard deviation ;

ME ≥ margin of error

α = 98% ; At 98% confidence level ;Zcritical = 2.326

n ≥ (2.326 * 400) / 100

n ≥ 930.4 / 100

n ≥ 9.304

n = 10

7.3

step-by-step explanation:

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: