Find the perimeter of these figures *
please*

The perimeter of figure a is 44 inches, the perimeter of figure b is 72 inches.

Step-by-step explanation:

The sides of figure a is 8; 2; 3; 12; 2; 12; 3; 2, to get the perimeter, add all the sides together, which will be 8 + 2 * 2 + 3 * 2 + 12 * 2 = 8 + 4 + 6 + 24 = 12 + 30 = 42 inches. The sides of figure b is 3; 3; 3; 3; 13; 13; 5; 5; 5; 5; 7; 7, to get the perimeter, add all the sides together, which will be 3 * 4 + 13 * 2 + 5 * 4 + 7 * 2 = 12 + 26 + 20 + 14 = 32 + 40 = 72 inches.

a) 44

2 + 8 + 2 + 8 + 12 + 12 = 44

b) 72

13 + 13 + 3 +3 +3 +3 +5 +5 +5 +5 +7 +7 = 72

Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204