3. x2 - 6x + 9 = 0
Are the real​

1 real solution: x=3

Step-by-step explanation:

By factoring:

x^2-6x+9=0

(x-3)^2=0

x-3=0

x=3

So yes there's 1 real solution which is x=3.

You can also check the discriminant:

b^2-4ac

(-6)^2-4(1)(9)

36-36

0

Since the discriminant is 0, there can only be 1 real solution.

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7

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step-by-step explanation: