lines p and q line in the coordinate plane. An equation for line p is y=0.36x-600. The slope of line q is 0.2 less than the slope of line p. what is the slope of line q?

y = -1/3x -3

Step-by-step explanation:

Lines

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point-slope form.

y = 3x + 5 is q. It has a slope of 3. So, p will have a slope of -1/3.

y - y1 = m ( x - x1)

y - (-5) = -1/3 ( x - 6)

y + 5 = - 1/3x + 2

y = -1/3x - 3

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.