Janessa is playing a board game with two friends. Using a single die, one friend rolled a four, and the other friend rolle a three. Janessa needs to roll a number higher than both friends in order to win the game, and she wants to calculate
her probability of winning.
How many desired outcomes should Janessa use in her probability calculation?

A. 3
B. 6
C. 4
D. 2

D. 2

Step-by-step explanation:

The only possible outcomes that Janessa could possibly calculate would be 5 and 6. This is because a single die has 6 possible outcomes. If Janessa's friends rolled a 3 and a 4, and Janessa needs to roll something higher, then the only higher possible outcomes would be a 5 or a 6. Meaning that Janessa can only use a total of 2 desired outcomes for her to actually win the game.

sorry i need more points

Step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11