A train moving at 40km/h applies brakes so that there is a constant 0.5m/s².find the time taken before the train stops. ​

t = 22.22 s

Step-by-step explanation:

Given that,

The initial speed of the train, u = 40 km/h

Acceleration of the train, a = 0.5 m/s²

Finally, it stops, v = 0

We need to find the time taken by it to stop. using first equation of motion to find it such that,

So, it will take 22.22 seconds to stop.

28

step-by-step explanation:

because that's the answer

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4