A student bought some markers in a pads of paper if the marker cost $2 each in the pads of paper cost $4 each he brought a items and all and spent $26 how many markers and how many pads of paper did he buy?​

$4

Step-by-step explanation:

We need to set up an algebraic expression to solve this problem:

 Let n= cost of a notepad

Let p= cost of a pen

 First set up an expression for Cynthia's purchase:

 cost of notepads*number of notepads + cost of pens*number of pens = total cost

 n*2 + p*3 = 40.30

 Rewrite as:

2n + 3p = 40.30

 Next, set up an expression for Annie's purchase:

 Here we will be using the same variables

  n*3 + p*5 = 61

 Rewrite as:

 3n + 5p =61

 Now, set up a system of equations:

 2n + 3p = 40.30

3n + 5p =61

 A system of equations can be solved in several ways, here I will use the addition/elimination method

For this method one of the variables must be able to be eliminated

Step 1: Pick a variable to eliminate

Here I will eliminate n

Step 2: make the selected variables in the equations equal and opposite so that they cancel out when the equations are added together

(2n + 3p = 40.30)(-3)

(3n + 5p =61)(2)

-6n - 9p = -120.90

6n + 10p = 122

Step 3: add vertically

-6n - 9p = -120.90

6n + 10p = 122

         p  =  1.10

Step 4: Figure out the other variable by inputting the answer you just got back into the original equation

2n + 3(1.10) = 40.30

2n + 3.30 = 40.30

      -3.30      37

         2n = 37

        /2     /2

         n = 18.5

One notebook = $18.50

One pen= $1.10

 18.50+1.10= $19.60

 2nd step

We must first set up an algebraic expression

 total=15 pencils

total=9 pens

 The total amount is the price of one pencil*15

 To figure out one pencil:

10 pencils are $24

1 pencil is $2.40

 Total= $36

 9 pens = 36

Therefore 1 pen is $4

  2087568668/1  

step-by-step explanation:

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step-by-step explanation: