the probabilities that amy and tess will arrive at party on time are 2/3 and 3/4 respectively. Find the probability that a. amy will arrive on time while tess is not

1/6

Step-by-step explanation:

Probability that any arrives on time = 2/3

Probability that teaa arrives on time = 3/4

Probability that teas will not arrive in time = 1 - P(tess arrives on time) = 1 - 3/4 = 1/4

Hence,

The probability that Amy arrives in time and tess does not equals

2/3 * 1/4 = (2*1) / (3*4) = 2 / 12 = 1/6

answer: i'm going in

step-by-step explanation:

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer