Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially atx1 = 12.2 mm. In this configuration, q1 exerts a repulsive force of 2.62 µN on q2. Particle q2 is then moved to x2 = 18.4 mm. What is the force (magnitude and direction) that q2 exerts on q1 at this new location? (Give the magnitude in µN.)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

i’m sorry but i don’t know sorry

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: