In ΔJKL, the measure of ∠L=90°, LK = 12, KJ = 37, and JL = 35. What ratio represents the secant of ∠K?

Sec <K  = 37/12

Step-by-step explanation:

Given the following measure

∠L=90°

LK = 12

KJ = 37, and

JL = 35.

Considering angle K

JL = opposite

KJ =hypotenuse

LK = adjacent

Using SOH CAH TOA identity

Cos theta = adj/hyp

Cos m<K = LK/KJ

cos m<K = 12/37

Since sec theta = 1/cos thets

Sec <K = 1/cos<K

Sec <K = 1/(12/37)

Sec <K  = 37/12

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8