A parabola has its minimum point at (3,-5) and the y coordinate of the y-intercept is -2. What is the equation of the parabola?

y = x² - 2x - 2

Step-by-step explanation:

x-coordinate of the vertex of a parabola is ( )

y = f(x) = ax² + bx + c

(x, y) ∈ f(x)

~~~~~~~~~

{ (0, - 2), (3, - 5) } ⊂ { (x, y): y = ax² + bx + c }

a(0)² + b(0) + c = - 2 ⇒ c = - 2

a(3)² + b(3) + ( - 2) = - 5  

9a + 3b - 2 = - 5 ⇒ 3a + b = - 1

= 3 ⇒ b = - 6a

3a + ( - 6a) = - 1

a =

b = - 2

y = x² - 2x - 2

eveidence i thing that

step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!