Can some one explain how to do it please. I am so confused.​

Hi there!

Your job, at least on this triangle, is pretty simple. This is a 45-45-90 triangle.

Because this is a 45-45-90 triangle, both legs are 5. That leaves us to find the hypotenuse, x.

And a 45-45-90 triangle's hypotenuse is easy. You just take the measure of one of the legs, or 5 in this case, and stick a right next to it. So your answer will be:

I hope this helps! :)

x = -2

y = 848

step-by-step explanation:

plug in the numbers

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.