There are two numbers and the first is larger than the second, Three times the larger number plus the smaller number is forty, Twice the smaller number
plus one is equal to the larger number. Find both numbers,

the smaller number is 37/7, the larger one is 81/7

Step-by-step explanation:

Assume the smaller one is x, and the bigger one is y. Then we got that x+3y=40, 2x+1=y.

from y=2x+1, we can replace y in "x+3y=40" with "2x+1".

x+3(2x+1)=40, so x=37/7

y=2x+1=81/7

dwe

step-by-step explanation:

ewd

add 5 subtract 1

step-by-step explanation: