The base of a triangle is eleven feet less than four times its height. If the sum of the lengths of
the base and height of the triangle is 49 feet,
find the area of the triangle.

129 Feet

Step-by-step explanation:

You can make an equation where Height=h, and Base=b. So going backwards with the first question, the base will equal 4 times the height: b=4h, and 11 less. b=4h-11. The the other equation will be just that the base plus the height is 49. b+h=49. Then you put that into y=mx+b form. The first equation already is, and the second equation would be b=49-h. So, since the equations equal the same things, you throw away the b. Then you make a new equation by having 4h-11 equal 49-h. Since this is true seeing as they are the same triangle. Then you just use propreties of equality for the equation. You end up with 5h=60. The. You divide 60 by 5 to make 5h just equal h. So you get h=6. Then, like the qeuation said, the base (unknown) plus the height (6) is 49. So to get from 6 to 49, the answer is 43. The formula for that area of a triangle is (base x height) /2 = area. So 43 times 6 is 258. Then divided by 2 is 129. So the area of the triangle is 129.

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