PLEASE HELP ASAP GEOMETRY I AM LITERALLY DYING!! 100 POINTS REAL ANSWERS ONLY OR YOU WILL BE REPORTED AND GET NO POINTS! Let’s design a new ferris wheel!! Create a sketch of a new Ferris wheel. This new ferris wheel must have an arc length measuring 3 25π feet. What is the equation of your new ferris wheel if the center must be at least 60 feet from the ground? Be sure to show and explain all work.

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  x^2 +(y -61)^2 = 625/36

Step-by-step explanation:

The graph of the above equation is attached.

If the circumference of the wheel is 25π/3 feet, the diameter is ...

  d = C/π = (25/3π)/π = 25/3 . . . feet, about 8.33 feet

The radius will be half that value, or 25/6 feet.

For a center point (h, k) and radius r, the equation of a circle is ...

  (x -h)^2 +(y -k)^2 = r^2

You want the center to be more than 60 feet from the ground, so we can make it be 61 feet. The horizontal location is not specified, so we can make it zero.

This means we apparently want the equation for a circle of radius 25/6 feet with a center that is (x, y) = (0, 61). The equation of this circle is ...

  x^2 +(y -61)^2 = 625/36

ANSWER:

Circumference = 25π/3

Then their diameter = 25/3 ft and r = 25/6 ft.

Now, For a center point (h, k) of radius r the equation of circle is (x - h)² + (y - k)² = r².

We can take (h, k) = (0, 61) as it should be at least 60 ft.

So, equation becomes

NOTE: See picture attached.

just needed some points but try socratic