Help me answer this question please​

9514 1404 393

  x = ∛4 ≈ 1.587 m

  y = (∛4)/2 ≈ 0.794 m

Step-by-step explanation:

Short answer:

An open-top box will use minimum material when it has the shape of half a cube. That is, the x-dimensions will be ...

  x = ∛(2·2 m³) = ∛4 m

The y-dimensions will be half that:

  y = x/2 = (∛4)/2 m

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Long answer:

The volume is ...

  V = x^2·y

so the y-dimension is ...

  y = V/x^2

The area of the sides and bottom will be ...

  A = 4xy + x^2

  A = 4x(2/x^2) +x^2 = 8/x +x^2

The area is minimized when the derivative of this is zero.

  A' = 0 = -8/x^2 +2x

  x^3 = 4 . . . . . . . divide by 2 and rearrange

  x = ∛4 . . . . . . . . cube root

  y = 2/x^2 = 2∛4/4

  y = (∛4)/2

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Additional comment

If you follow the numbers through, you see that the value under the cube-root radical is twice the volume. This is the result we used in the "short answer."

i dont know sorry

step-by-step explanation: