Pete runs an ice cream stand that also sells snow cones served in paper cones. The paper cones he usually uses have a radius of 3 inches and a height of 4 inches, but his supplier is out of them. As a replacement, he purchases paper cones with a radius of 4 inches and a height of 3 inches. How do the volumes of the original and replacement cones compare? A. The replacement cone holds 3π cubic inches more than the original. B. The original and replacement cones have the same volume. C. The replacement cone holds π cubic inches more than the original. B. The original cone holds π cubic inches more than the replacement.

The correct answer is;

The replacement cone holds 4·π cubic inches more than the volume of the original cone  

Step-by-step explanation:

The given measurements of the cones are;

The radius of the original cone, r₁ = 3 inches

The height of the original cone, h₁ = 4 inches

The radius of the replacement cone, r₂ = 4 inches

The height of the replacement cone, h₂ = 3 inches

The volume of a cone, V = (1/3)·π·r²·h

The volume of the original cone, V₁ = (1/3)·π·r₁²·h₁

∴ V₁ = (1/3) × π × (3 in.)² × 4 in. ≈ 37.7 in.³

The volume of the replacement cone, V₂ = (1/3)·π·r₂²·h₂

∴ V₂ = (1/3) × π × (4 in.)² × 3 in. ≈ 50.27 in.³

The ratio of the volume of the two cones is given as follows;

Volume ratio = V₁/V₂

∴ Volume ratio = (1/3) × π × (3 in.)² × 4 in. /((1/3) × π × (4 in.)² × 3 in.) = 3/4

The difference in volume, ΔV = V₂ - V₁ = (1/3) × π × ((4 in.)² × 3 in. - (3 in.)² × 4 in. = 4·π in.³

Therefore, the volume of the replacement cone is 4·π in.³ more than the volume of the original cone.

the answer for this question is 38

the answer is y = 11.54

hope this : )