If point P, located at (6, -2), is rotated 270 counterclockwise about the origin, what
are the coordinates of its image, P'?
A. (6,2)
B. (2,6)
C. (-2,-6)
D. (-2,6)
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SPONGEBOB GANG FOR LIFe

Step-by-step explanation:

PATRICK STAR IS BAD

hey i think it is -2,-6

Step-by-step explanation:

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²