Given
The vertex ( -2 , 5 ) and a random point ( -4, 3 )
Find the quadratic equation

quadratic equation

y=-1/32(x+2)²+5

Step-by-step explanation:

we have

let vertex be (p,q)=(-2,5)

random point (x,y)=(-4,3)

we have

y=a(x-p)²+q

3=a(6-(-2))²+5

3=64a+5

3-5=64a

a=-2/64=-1/32

now

quadratic equation

y=-1/32(x+2)²+5

i'm going to search it

step-by-step explanation: