the width of a rectangle is 8 feet and the diagnal length of the rectangle is 13 feet which measurement is closest to the length of this rectangle in feet

Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself

Step-by-step explanation:

Okay so you have a weigh of 8 and a diagonal of 13.

If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.

Pythagorean theroum: a^2+b^2=c^2

Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.

In this case I’m substituting a for 8.

8^2+b^2=13^2

Solve the squares

64+b^2= 169

Isolate the b

b^2=105

Now square root 105

√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.

the solution is h=10 because you add 9 to each side of the equation.

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,