Which is an equation in point-slope form for the given point and slope? Point: (1.9); Slope: 5 A: y-1=5(x+9)
B: y-9=5(x+1)
C: y-9=5(x-1)
D: y+9=5(x-1)​

answer is D

from y-y'=m(x-x') ,where m is slope and x' and y' are our points then ;

given are;

m=5, x' =1 and y' =9

By substituting our given

y-9=5(x-1)

50.6

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)