The sum of 4 consecutive integers is 40 what is the third number in this sequence?

Let's represent the numbers by : x, x+1, x+2, x+3
x+x+1+x+2+x+3=40                     The third number in the sequence is x+2
4x+6=40                                           8.5+2=10.5
4x+6-6=40-6                               Therefore the third number in the sequence is
4x=34                                             10.5
4x/4=34/4
x=8.5

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