Write a system of equations to solve the following problem. let c be the number of child tickets and a be the number of adult tickets.
each child ticket for a ride costs $3, while each adult ticket costs $5. if the ride collected a total of $115, and 33 tickets were sold, how many of each type of ticket were sold?

27 small and 6 large

20 small and 10 large

10 small and 20 large

8 small and 22 large

this next question confuses
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write a system of equations to solve the following problem. let c be the number of child tickets and a be the number of adult tickets.
each child ticket for a ride costs $3, while each adult ticket costs $5. if the ride collected a total of $115, and 33 tickets were sold, how many of each type of ticket were sold?
(options below)

3c + 5a=115

a+c=33

A=8

C=25

Step-by-step explanation:

In this case you just have to know that the price of the child tickets are $3, so thats the constant thas goes along with the C and the price for the adult tickets is $5 and that is the constant number that goes with the A, so the first equations would be:

3c + 5a=115

And you know that they sold 33 tickets so the total number of adult tickets added up to the total number of child tickets should be 33 so the second equation should be this:

a + c= 33

You just have to eliminate the c by multiplying the second equation by -3

3c + 5a=115  =       3c+ 5a= 115

(a + c= 33) -3=       -3c -3a= -99

You add both equations and it will end up like this:

+5a - 3a= 115-99

2a=16

A=8

So your first answer is A=8

and to solve the value for C you just put the value of A into one of the eqquations of the system:

A+C=33

C=33-8

C=25

the size of the resulting matrix is 1-by-3.

step-by-step explanation:

the size of the two matrices given are as follows:

no .of rows of matrix 1 = 1

no .of columns of matrix 1 = 3

no .of rows of matrix 1 = 3

no .of columns of matrix 1 = 3

to find the size of the resulting matrix without actually solving the multiplication of the matrix, this is what you do:

if resulting matrix = matrix 1 * matrix 2

no. of rows of the resulting matrix = number of rows of matrix 1

no. of columns of resulting matrix = number of columns of matrix 2

note: the order of the matrices matter!

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.