Find the simple interest on the following amounts: a K4000 invested at 6% p. a. for 4 years
b K23 000 invested at 6.5% p. a. for 8 years
K580 borrowed at 5% p. a. for 9 months
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a. Simple interest = K960

b. Simple interest = K11,960

c. Simple interest = K261

Step-by-step explanation:

Given the following data;

a. Principal = K4000

Interest rate = 6%

Time = 4 years

To find the simple interest;

Mathematically, simple interest is calculated using this formula;

Where;

S.I is simple interest.

P is the principal.

R is the interest rate.

T is the time.

Substituting into the equation, we have;

S.I = K960

b. Principal = K23 000

Interest rate = 6.5%

Time = 8 years

To find the simple interest;

Substituting into the formula, we have;

S.I = K11,960

c. Principal = K580

Interest rate = 5%

Time = 9 months

To find the simple interest;

S.I = K261

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?