If the cos of angle x is eight seventeenths and the triangle was dilated to be two times as big as the original, what would be the value of the cos of x for the dilated triangle? PLS HELP ASAP!

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation:

answer: 414,377,008

step-by-step explanation:

just multiply it

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180