Mathematics, 07.04.2021 20:40 absoul1143
Solve the equation x^5 โ 4x^4 + 4x^3 + 2x^2 โ 5x + 2 = 0 in the real number system.
x = โ1 with multiplicity 3, x = 1, x = 2
x = โ1, x = 1, x = 2 with multiplicity 3
x = โ1, x = 1 with multiplicity 2, x = 2 with multiplicity 2
x = โ1, x = 1 with multiplicity 3, x = 2
Answers: 3
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Solve the equation x^5 โ 4x^4 + 4x^3 + 2x^2 โ 5x + 2 = 0 in the real number system.
x = โ1 with mul...
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