Johnny was able to drive an average of 29 miles per hour faster on his car after the traffic cleared. He drove 30 miles in traffic before it cleared and the drove another 176 miles. If the total trip took 6 hours, then what was his average speed in traffic?

15 mph

Step-by-step explanation:

Before traffic cleared:

distance = 30 miles

average speed = s

time = t

d = st

30 = st

After traffic cleared:

distance = 176 miles

average speed = s + 29

time = 6 - t

d = st

176 = (s + 29)(6 - t)

30 = st

s = 30/t

176 = (30/t + 29)(6 - t)

176t = (30 + 29t)(6 - t)

176t = 180 - 30t + 174t - 29t^2

29t^2 + 32t - 180 = 0

(29t + 90)(t - 2) = 0

t = -90/29 or t = 2

Time must be a positive number, so we discard the solution t = -90/29.

t = 2

30 = st

30 = s * 2

s = 15

15 mph

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

step-by-step explanation:

there are 36 inches in a yard

25 : 36 = 0.69 yards (you can round to 0.70)