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Mathematics, 07.04.2021 20:20 audrilynn1679
Binh solved this system of equations by graphing.
Line 1: y = negative one-half x minus three-halves. Line 2: y = x minus 3.
Binh’s Graph
On a coordinate plane, a line with equation y = x minus 3 goes through (negative 3, 0) and (0, 3). A line with equation y = negative one-half x minus three-halves goes through (negative 3, 0) and (1, negative 2).
Which statements identify the errors Binh made? Check all that apply.
Binh incorrectly graphed the equation y = x minus 3.
Binh should have graphed the y-intercept of y = x minus 3 at (0, negative 3).
Binh should have graphed the y-intercept of y = negative one-half x minus three-halves at (0, negative one-half).
Binh incorrectly graphed the equation y = negative one-half x minus three-halves.
Binh should have found the point of intersection to be (1, negative 2).
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You know the right answer?
Binh solved this system of equations by graphing.
Line 1: y = negative one-half x minus three-halve...
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