What is the equation of the line that passes through the point (6, -6) and has a
slope of 5/3

Y=mx+b is the equation of any straight line

slope is 5/3 so y=5/3x+b

point is (6,-6) so plug the coordinates intk the equation

6 is the x coordinate and -6 is the y coordinate

y=5/3x+b
(-6)=5/3(6)+b
-6=-10+b
+10 +10
4=b

so equation is
y=5/3x+4

if u have any questions lmk