The rectangle below has an area of 8x^5+12x^3+20x^28x 5
+12x
3
+20x
2
8, x, start superscript, 5, end superscript, plus, 12, x, cubed, plus, 20, x, squared.
The width of the rectangle is equal to the greatest common monomial factor of 8x^58x
5
8, x, start superscript, 5, end superscript, 12x^312x
3
12, x, cubed, and 20x^220x
2
20, x, squared.
What is the length and width of the rectangle?

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

yes

step-by-step explanation:

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2

0

step-by-step explanation:

equals the constant of proportionality.

solve for