An airplane travels about 1500km in a straight line between toronto and winnipeg . however, the plane must climb to 10 000 m during the first 200km. then it must descend 10 000 m during the final 300km

1. how much distance do the climb and desent add to the flight?

Climbing and descending add to the flight 416 m

Step-by-step explanation:

The plane must climb to 10 km during the first 200 km. This forms a right triangle, where 10 and 200 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:

√(10² + 200²)

The plane must descend 10 km during the final 300km. This forms a right triangle, where 10 and 300 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:

√(10² + 300²)

If the airplane climbed during 300 km and descended during 200 km, then during 1500 - 200 - 300 = 1000 km it doesn't climb or descend.

The distance added by climbing and descending is:

1000 + √(10² + 200²) + √(10² + 300²) - 1500 = 0.416 km or 416 m

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )