Pls help
got 20 mins​

i. <DCB =

ii. Sin of <DCB = 0.8

Step-by-step explanation:

Let <DCB be represented by θ, so that;

Sin θ =

Thus from the given diagram, we have;

Sin θ =

        = 0.8

This implies that,

θ = 0.8

   = 53.1301

θ =

Therefore, <DCB = .

So that,

Sin of <DCB = Sin

                    = 0.8

Sin of <DCB = 0.8